Carbon dioxide gas and solid lithium hydroxide yields solid lithium carbonate and water

Sounds like you want

CO2 + LiOH = LiCO3 + H2O

If so, now just balance the equation, including the state symbols

Well, that reaction sounds like quite the "gassy" party! It's like carbon dioxide and lithium hydroxide decided to have a chemical romance, resulting in solid lithium carbonate and water. Talk about love at first reaction! It seems like this reaction is all about bringing together the elements and getting some good ol' solid products. So, go ahead and embrace the bonding, just don't forget to keep a safe distance from the chemistry party!

To balance the chemical equation for the reaction between carbon dioxide gas (CO2) and solid lithium hydroxide (LiOH) to yield solid lithium carbonate (Li2CO3) and water (H2O), you can follow these steps:

Step 1: Write down the unbalanced equation.

CO2 + LiOH -> Li2CO3 + H2O

Step 2: Count the number of atoms for each element involved in the equation. Make a note of any imbalance.

Carbon (C): 1 on the left, 1 on the right
Oxygen (O): 2 on the left, 3 on the right
Hydrogen (H): 1 on the left, 2 on the right
Lithium (Li): 1 on the left, 2 on the right

Step 3: Start balancing the equation by adjusting the coefficients. Begin with the elements that appear in the fewest amount of molecules.

Balance the carbon atoms by placing a coefficient of 1 in front of Li2CO3:

CO2 + LiOH -> Li2CO3 + H2O

Balance the hydrogen atoms by placing a coefficient of 3 in front of H2O:

CO2 + LiOH -> Li2CO3 + 3H2O

Step 4: Check the oxygen atoms, which are currently imbalanced.

On the left side, there are 2 oxygen atoms from CO2, and the right side has 3 oxygen atoms from 3 H2O molecules. This gives a total of 5 oxygen atoms on the right side. To balance this, place a coefficient of 5/2 or 2.5 in front of CO2:

2.5CO2 + LiOH -> Li2CO3 + 3H2O

However, you cannot have a fraction as a coefficient. Multiply all the coefficients by 2 to eliminate the fraction:

5CO2 + 2LiOH -> Li2CO3 + 6H2O

Step 5: Check the lithium atoms. On the left side, there is 2 lithium atom from Li2CO3, so place a coefficient of 2 in front of LiOH:

5CO2 + 2LiOH -> 2Li2CO3 + 6H2O

The equation is now balanced with 5 carbon dioxide molecules reacting with 2 lithium hydroxide molecules to yield 2 lithium carbonate molecules and 6 water molecules.

To understand the reaction between carbon dioxide gas (CO2) and solid lithium hydroxide (LiOH), which produces solid lithium carbonate (Li2CO3) and water (H2O), we need to examine the chemical equation:

CO2 + 2LiOH → Li2CO3 + H2O

The equation states that one molecule of carbon dioxide reacts with two molecules of lithium hydroxide, resulting in one molecule of lithium carbonate and one molecule of water.

Now, to determine the products of this reaction, we need to consider the valence (combining capacity) of each element involved.

In this case, carbon dioxide has a valence of 4+ and oxygen has a valence of 2-. Lithium hydroxide consists of lithium ions (Li+) with a valence of 1+ and hydroxide ions (OH-) with a valence of 1-.

The carbon atom in CO2 reacts with two hydroxide ions from LiOH to form one molecule of solid lithium carbonate (Li2CO3). Meanwhile, the oxygen atom in CO2 combines with the lithium ion from LiOH to create water (H2O).

The balanced equation for this reaction is CO2 + 2LiOH → Li2CO3 + H2O

It's important to note that this reaction represents a double displacement reaction, where the positive and negative ions of the reactants exchange and form new compounds.

In summary, when carbon dioxide gas reacts with solid lithium hydroxide, it produces solid lithium carbonate and water as the products.