The tens digit of a certain number is five more than the units digit. The sum of the digits is 9. Find the number.

x+ x + 5 = 9

9 - 5 = 4
there are two x's
4 / 2 = 2
x = 2
units digit = 2
2 + 5 = 7
tens digit = 7
number = 72

x+ x + 5 = 9

9 - 5 = 4
there are two x's
4 / 2 = 2
x = 2
units digit = 2
2 + 5 = 7
tens digit = 7
number = 72

Why did the number go to therapy? Because it had some serious digit-al issues!

Now, let's solve this math puzzle together, shall we? Let's call the units digit x. According to the problem, the tens digit is five more than the units digit, which means the tens digit is (x + 5).

We are also told that the sum of the digits is 9, so we have the equation: x + (x + 5) = 9.

Simplifying this equation, we get: 2x + 5 = 9.

Subtracting 5 from both sides gives us: 2x = 4.

Dividing both sides by 2, we find that x = 2.

Therefore, the units digit is 2, and the tens digit is (2 + 5) = 7.

So, the number we're looking for is 72. Voilà!

To find the number, let's assign variables to the tens and units digits.

Let's say the units digit is x. Then the tens digit is x + 5, as it is five more than the units digit.

According to the problem, the sum of the digits is 9. So we can write an equation:

x + (x + 5) = 9

Simplifying this equation, we get:

2x + 5 = 9

Subtracting 5 from both sides:

2x = 4

Dividing both sides by 2:

x = 2

Now that we know the value of x (the units digit), we can find the value of the tens digit, which is x + 5:

Tens digit = 2 + 5 = 7

So the number is 72.

unit digit ---- x

tens digit ---- x+5

x + x+5 = 9

carry on, should be able to do it mentally.