A man has a mass of 80.0kg is standing on the surface of the earth.(a)calculate the magnitude of the attractive force that the earth exerts on the man
To calculate the magnitude of the attractive force that the Earth exerts on the man, you can use the formula for Newton's law of universal gravitation:
F = (G * m1 * m2) / r^2
Where:
F is the magnitude of the attractive force between two objects
G is the gravitational constant, which is approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2
m1 and m2 are the masses of the two objects (in this case, the man and the Earth)
r is the distance between the centers of the two objects (we assume the man and the Earth have a negligible radius, so we consider the distance as the radius of the Earth)
Given that the mass of the man is 80.0 kg, and the mass of the Earth is approximately 5.972 × 10^24 kg, we can substitute these values into the formula.
m1 = 80.0 kg
m2 = 5.972 × 10^24 kg
G = 6.67430 × 10^-11 m^3 kg^-1 s^-2
r = radius of the Earth (approximately 6,371 km or 6,371,000 meters)
Now let's calculate the magnitude of the attractive force:
F = (G * m1 * m2) / r^2
F = (6.67430 × 10^-11 m^3 kg^-1 s^-2 * 80.0 kg * 5.972 × 10^24 kg) / (6,371,000 meters)^2
After evaluating this expression, the magnitude of the attractiveness force that the Earth exerts on the man is approximately equal to 784 N (Newtons).