Factor by identifying a common factor in each term.
g) 6xy2 = (3x) (?)
h) 25a3b2 = (5a2b2) (?)
i) 6x + 6y + 6p
Factor:
j) x(x+2) + y (x + 2) - 5(x + 2)
k) 5y2 - 10y3
l) ax + ay + az
Factor:
m) yx(y+1) + 4x(y + 1) - 5(y + 1)
n) 6p2 - 3p3
o) 4x4 + 2x
Please help
instead of 25a3b2 = (5a2b2) (?), write exponent form this way:
25a^3b^2 = (5a^2b^2) (?)
In a way, all you need to ask is "What's missing to complete the multiplication"
e.g. 5 times "what" will give me 25" ? ----> 5
a^2 times what will give me a^3 ? ----> another a
b^2 times what will give me b^2 ? -----> clearly 1
so 5a^3b^2 = (5a^2b^2) (5a)
do the others the same way, let's see your answers.
Let's go through each of the expressions and identify the common factors in each term.
g) 6xy2 = (3x) (?)
In this case, the common factor is 3x, so we can factor out 3x from the given expression:
6xy2 = 3x * (2y2)
h) 25a3b2 = (5a2b2) (?)
The common factor here is 5a2b2, so we can factor it out:
25a3b2 = 5a2b2 * (5ab)
i) 6x + 6y + 6p
In this expression, there is no common factor for all the terms, so it cannot be factored further.
j) x(x+2) + y (x + 2) - 5(x + 2)
In this case, we have a common factor in each term, which is (x + 2). We can factor it out:
x(x + 2) + y(x + 2) - 5(x + 2) = (x + 2)(x + y - 5)
k) 5y2 - 10y3
In this expression, the common factor is 5y2, so we can factor it out:
5y2 - 10y3 = 5y2(1 - 2y)
l) ax + ay + az
Here, the common factor is simply a, so we can factor it out:
ax + ay + az = a(x + y + z)
m) yx(y+1) + 4x(y + 1) - 5(y + 1)
In this case, the common factor is (y + 1). We can factor it out:
yx(y + 1) + 4x(y + 1) - 5(y + 1) = (y + 1)(yx + 4x - 5)
n) 6p2 - 3p3
For this expression, there is no common factor, so it cannot be factored further.
o) 4x4 + 2x
In this example, the common factor is 2x. We can factor it out:
4x4 + 2x = 2x(2x3 + 1)
I hope this helps! Let me know if you have any further questions.