The vertices of ΔABC are A(2, –5), B(–3, 5), and C(3, –3). The triangle is reflected over the x-axis. Use arrow notation to describe the original triangle and its reflection.
a. A(2, –5), B(–3, 5), C(3, –3) --> (2, –5), (–3, 5), (3, –3)
b. A(2, –5), B(–3, 5), C(3, –3) --> (–2, 5), (3, –5), (–3, 3)
c. A(2, –5), B(–3, 5), C(3, –3) --> (–2, –5), (3, 5), (–3, –3) ++
d. A(2, –5), B(–3, 5), C(3, –3) --> (2, 5), (–3, –5), (3, 3)
The point c(x,y) is reflected over the x-axis. Use arrow notations to describe the original point and its reflection.
a. (x,y) --> (x,2y)
b. (x,y) --> (-x,y)
c. (x,y) --> (-x,-y)
d. (x,y) --> (x,-y) +++++
is the first answer (2, –5), B(–3, 5), C(3, –3) --> (2, 5), (–3, –5), (3, 3)
the 2nd answer is correct ... use it to fix the 1st answer
yes
To answer this question, we need to understand the reflection over the x-axis.
When a point is reflected over the x-axis, the y-coordinate changes sign while the x-coordinate remains the same.
Let's examine the given points: A(2, -5), B(-3, 5), and C(3, -3).
To reflect these points over the x-axis, we keep the x-coordinate the same, but change the sign of the y-coordinate.
Reflecting A(2, -5) over the x-axis gives us A(2, 5).
Reflecting B(-3, 5) over the x-axis gives us B(-3, -5).
Reflecting C(3, -3) over the x-axis gives us C(3, 3).
So, the correct answer is: c. A(2, -5), B(-3, 5), C(3, -3) --> (2, 5), (-3, -5), (3, 3).