In a certain species of rabbit, black fur is dominant to white fur. A male rabbit with black fur that is a heterozygote is crossed with a female rabbit with black fur, which is also a heterozygote. Using a Punnett square, show what the genotypes and phenotypes are for the offspring. Write your answers in a complete sentence.
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To determine the genotypes and phenotypes of the offspring, we can use a Punnett square. Let's represent the dominant black fur allele as "B" and the recessive white fur allele as "b".
First, let's write down the genotypes of the parent rabbits. The male rabbit is a heterozygote, meaning it has one black fur allele (B) and one white fur allele (b), so its genotype is Bb. The female rabbit is also a heterozygote, so her genotype is Bb as well.
To create a Punnett square, we will put the possible alleles from each parent along the top and left side of a 2x2 grid. In this case, the male rabbit's gametes can be either B or b, and the female rabbit's gametes can also be either B or b.
The Punnett square would look like this:
B b
------------------
B | BB Bb
------------------
b | Bb bb
Now, let's determine the genotypes and phenotypes of the offspring by combining the alleles in each corresponding box.
The Punnett square shows that there are four possible combinations of alleles for the offspring:
- Two offspring have the genotype BB, which means they inherit two black fur alleles. Their phenotype is black fur.
- One offspring has the genotype Bb, which means it inherits one black fur allele and one white fur allele. Its phenotype is black fur.
- One offspring has the genotype bb, which means it inherits two white fur alleles. Its phenotype is white fur.
Therefore, the genotypes of the offspring are BB, Bb, Bb, and bb, and the corresponding phenotypes are black fur, black fur, black fur, and white fur, respectively.