eric has a pair of identical number cubes.the face of each of each cube are numbered 1-6.eric will roll the cubes both at the same time.what is the probability that the numbers showing face-up after the roll will be multiples of 3?

A)2/9
B)1/3
C)1/6
D)1/9

Give me assistance por favore, i think it's B

Do the math here. The numbers on a die are 1 to 6 (1,2,3,4,5,6) and there are two multiples of 3 in 1 -6, 3 and 6. so that's 2 numbers out of 6, 2/6, simplified would be?

1/3, so B was right?

There are only 2 faces on each die that are multiples of 3: 3,6

So, the chance that a die will show 3 or 6 is 2/6 = 1/3
The chance that both dice will show one of those faces is
1/3 * 1/3 = 1/9

tysm

To find the probability that the numbers showing face-up after rolling the cubes are multiples of 3, we need to determine the total number of outcomes and the number of favorable outcomes.

Total number of outcomes:
Since there are 6 faces on each cube and two cubes, the total number of outcomes is 6 * 6 = 36.

Number of favorable outcomes:
To find the favorable outcomes, we need to identify the numbers that are multiples of 3. These are: 3, 6, and 9. Each number can appear on either of the two cubes in the pair. So there are 2 possible outcomes for each multiple of 3. Therefore, the number of favorable outcomes is 2 * 3 = 6.

Now we can calculate the probability:
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Probability = 6 / 36
Simplifying the fraction, we get 1 / 6.

Therefore, the probability that the numbers showing face-up after rolling the cubes will be multiples of 3 is 1/6.

The correct answer is C) 1/6.

Yep, that's right!