Iron (III) Nitrate reacts with Sodium Carbonate to form a precipitate.

Be sure to indicate oxidation states (charges on each ion) & the precipitate.

Skeletal Equation:

Ionic Equation: (assume all ions are aqueous, dissociated free ions)

NET Ionic Equation:

Balanced Equation:

Spectator Ions:

2Fe(NO3)3 (aq) + 3Na2CO3 (aq) → Fe2(CO3)3 (s) + 6NaNO3 (aq)

To determine the skeletal equation and the subsequent steps, let's first write out the formulas of each compound involved:

Iron (III) Nitrate: Fe(NO3)3
Sodium Carbonate: Na2CO3

Now let's proceed to the step-by-step solution:

1. Skeletal Equation:
Fe(NO3)3 + Na2CO3 →

To determine the products formed, we need to identify the ions present in each compound.

Iron (III) Nitrate breaks down into the following ions:
Fe3+ and NO3-

Sodium Carbonate dissociates into the following ions:
2Na+ and CO3 2-

Now let's combine the ions to form the products:

Fe3+ + 3NO3- + 2Na+ + CO3 2- →

2. Ionic Equation:
To write the ionic equation, we write out all the ions involved, indicating their charges and states:

Fe3+ + 3NO3- + 2Na+ + CO3 2- → Fe3+ + 3NO3- + 2Na+ + CO3 2-

Since all ions are aqueous, we can cancel out the common ions on both sides. In this case, we have Fe3+, 3NO3-, and 2Na+ present on both sides of the equation.

3. NET Ionic Equation:
The net ionic equation is obtained by removing the spectator ions (ions that are present on both sides of the equation) from the ionic equation:

2CO3 2- →

4. Balanced Equation:
To balance the equation, we need to determine the correct coefficients that describe the stoichiometry of the reaction. Since the net ionic equation only contains one reactant, we can write the balanced equation directly:

Fe(NO3)3 + 3Na2CO3 → 3NaNO3 + Fe2(CO3)3

The balanced equation is Fe(NO3)3 + 3Na2CO3 → 3NaNO3 + Fe2(CO3)3.

5. Precipitate:
The precipitate is the solid formed when two aqueous solutions react. In this case, the precipitate is Fe2(CO3)3.

To determine the oxidation states (charges on each ion) and the precipitate formed in the reaction between Iron (III) Nitrate and Sodium Carbonate, you can follow these steps:

Step 1: Write the formulas for the reactants:
Iron (III) Nitrate: Fe(NO3)3
Sodium Carbonate: Na2CO3

Step 2: Determine the charges on each ion based on their position on the periodic table:
Iron (III) is a transition metal and can have multiple charges. The charge of Iron (III) is +3.
Nitrate (NO3) is a polyatomic ion with a charge of -1.
Sodium (Na) is an alkali metal with a charge of +1.
Carbonate (CO3) is a polyatomic ion with a charge of -2.

Step 3: Write the balanced ionic equation:
Fe(NO3)3(aq) + Na2CO3(aq) → FeCO3(s) + 3NaNO3(aq)
This equation represents the dissociation of the reactants into their respective ions. Note that the ionic equation assumes all ions are aqueous and dissociated.

Step 4: Write the balanced net ionic equation:
The net ionic equation only includes the species that undergo a chemical change during the reaction. In this case, the sodium ions (Na⁺) and nitrate ions (NO3⁻) are spectator ions because they remain unchanged on both sides of the equation. The net ionic equation is:
Fe³⁺(aq) + CO₃²⁻(aq) → FeCO₃(s)

Step 5: Write the balanced equation:
To balance the equation, make sure that the number of atoms of each element on the reactant side is equal to the number of atoms on the product side. For this reaction:
2Fe(NO3)3(aq) + 3Na2CO3(aq) → Fe2(CO3)3(s) + 6NaNO3(aq)

Step 6: Identify the precipitate:
From the balanced equation, the precipitate formed in this reaction is Fe2(CO3)3, which is iron(III) carbonate.

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