A solution of sodium chloride in water has a vapor pressure of 18.1 torr at 25°C. What is the mole fraction of NaCl solute particles in this solution? What would be the vapor pressure of this solution at 45°C? The vapor pressure of pure water is 23.8 torr at 25°C and 71.9 torr at 45°C and assume sodium chloride exists as Na+ and Cl - ions in solution.

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To find the mole fraction of NaCl solute particles in the solution, we need to use Raoult's law, which states that the vapor pressure of a solvent above a solution is directly proportional to the mole fraction of the solvent particles.

First, we need to find the mole fraction of water (solvent) in the solution using the given information.

Step 1: Calculate the mole fraction of water:
Mole fraction of water = 1 - Mole fraction of NaCl

Next, we can use the given vapor pressure values to find the mole fraction of water at each temperature.

Step 2: Calculate the mole fraction of water at 25°C:
Vapor pressure of water at 25°C = 23.8 torr
Mole fraction of water at 25°C = Vapor pressure of water at 25°C / Total vapor pressure of the solution at 25°C

Step 3: Calculate the mole fraction of water at 45°C:
Vapor pressure of water at 45°C = 71.9 torr
Mole fraction of water at 45°C = Vapor pressure of water at 45°C / Total vapor pressure of the solution at 45°C

Finally, we can use the mole fraction of water to find the mole fraction of NaCl at each temperature.

Step 4: Calculate the mole fraction of NaCl at 25°C:
Mole fraction of NaCl at 25°C = 1 - Mole fraction of water at 25°C

Step 5: Calculate the mole fraction of NaCl at 45°C:
Mole fraction of NaCl at 45°C = 1 - Mole fraction of water at 45°C

To find the vapor pressure of the solution at 45°C, we can use Raoult's law again.

Step 6: Calculate the vapor pressure of the solution at 45°C:
Vapor pressure of the solution at 45°C = Mole fraction of water at 45°C * Total vapor pressure of the solution at 45°C

Substituting the values into the equations above, you can find the answers.