If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
its 8 peeps
i had this question to for school and i figured it out to be 8
To find the length of the other leg of a right triangle, we can use the Pythagorean theorem. According to the theorem, in a right triangle, the sum of the squares of the lengths of the two legs is equal to the square of the length of the hypotenuse.
In this case, we know the length of one leg (15 units) and the length of the hypotenuse (17 units). Let's call the length of the other leg "x". Applying the Pythagorean theorem:
(15 units)^2 + x^2 = (17 units)^2
Simplifying the equation:
225 + x^2 = 289
Now, let's solve for x by isolating the variable on one side of the equation:
x^2 = 289 - 225
x^2 = 64
To find the value of x, we can take the square root of both sides of the equation:
√(x^2) = √64
x = 8
Therefore, the length of the other leg is 8 units.
a^2 + b^2 = c^2
15^2 + b^2 = 17^2
225 + b^2 = 289
b^2 = 64
b = ?