In a class of 40students,23 offer biology and 27 offer chemistry.Each student offers at least one of the two subjects.How many students offer both subjects?
I think you're using the word "offer" incorrectly. The question should read as follows:
In a class of 40students, 23 take biology and 27 take chemistry. Each student takes at least one of the two subjects. How many students take both subjects?
Now please wait for a math tutor to help you with the problem itself.
If you just add up 23 and 27, then you have counted twice those who take both. So, if there are x of those, then
23+27-x = 40
40
To find out how many students offer both biology and chemistry, you need to use the concept of the intersection of sets.
Step 1: Draw a Venn diagram with two overlapping circles, one for biology (B) and one for chemistry (C).
Step 2: Fill in the known information. In this case, we know that 23 students offer biology and 27 students offer chemistry.
Step 3: Determine the number of students in the intersection of the two sets, which represents those who offer both subjects. To do this, add up the number of students who offer biology (23) and the number of students who offer chemistry (27), and then subtract the total number of students (40):
Intersection = Biology + Chemistry - Total
Intersection = 23 + 27 - 40
Step 4: Calculate the intersection:
Intersection = 50 - 40
Intersection = 10
Therefore, 10 students offer both biology and chemistry subjects.