A nursery sells Kentucky Blue Grass seed for $5.75 per pound and Tall Fescue seed for$4.50 per pound. The nursery sells a mixture of the two kinds of seed for$5.25 per pound. Let k represent the amount of Kentucky Blue Grass seed the nursery uses in 5 pounds of the mixture.

1.Write an equation to represent the problem.

2.How much Kentucky Blue Grass does the nursery use in 5 pounds of the mixture?

3.How much Tall Fescue does the nursery use in 5 pounds of the mixture?

I k represents the amount of Blue Grass, then 5-k must be the amount of T.F. used

so....

575k + 450(5-k) = 525(5)

It solves quite nicely

Thank you

You are correct. The equation to represent the problem is:

575k + 450(5 - k) = 525(5)

To find the amount of Kentucky Blue Grass used in 5 pounds of the mixture, we substitute 5 into the equation for k:

575(5) + 450(5 - 5) = 525(5)
2875 + 0 = 2625
2875 = 2625

Therefore, the nursery uses 5 pounds of Kentucky Blue Grass in the mixture.

To find the amount of Tall Fescue used in 5 pounds of the mixture, we substitute 5 into the equation for k:

575(5) + 450(5 - 5) = 525(5)
2875 + 0 = 2625
2875 = 2625

Therefore, the nursery uses 0 pounds of Tall Fescue in the mixture.

To answer these questions, you need to set up an equation based on the given information and then solve for the unknown variables. Here's how you can do it:

1. Write an equation to represent the problem:
Let's use k to represent the amount of Kentucky Blue Grass seed the nursery uses in 5 pounds of the mixture. Since the nursery sells the mixture for $5.25 per pound, you can set up the equation as follows:
(Price of Kentucky Blue Grass * Amount of Kentucky Blue Grass) + (Price of Tall Fescue * Amount of Tall Fescue) = (Price of Mixture * Total Weight of Mixture)

In this case, the equation becomes:
(575 * k) + (450 * (5 - k)) = (525 * 5)

2. How much Kentucky Blue Grass does the nursery use in 5 pounds of the mixture?
To find the amount of Kentucky Blue Grass used in 5 pounds of the mixture, substitute 5 for the total weight of the mixture in the equation you set up in step 1. Then solve for k.

(575 * k) + (450 * (5 - k)) = (525 * 5)

Simplifying the equation:
575k + (450 * 5) - (450 * k) = 525 * 5
575k + 2250 - 450k = 2625
125k + 2250 = 2625
125k = 2625 - 2250
125k = 375
k = 375 / 125
k = 3

Therefore, the nursery uses 3 pounds of Kentucky Blue Grass in 5 pounds of the mixture.

3. How much Tall Fescue does the nursery use in 5 pounds of the mixture?
Since you already determined that k = 3 in step 2, you can substitute this value into the equation and solve for the amount of Tall Fescue used.

Amount of Kentucky Blue Grass = k = 3
Amount of Tall Fescue = 5 - k = 5 - 3 = 2

Therefore, the nursery uses 2 pounds of Tall Fescue in 5 pounds of the mixture.

I hope this helps! Let me know if you have any further questions.

Beans