Omar begins training for a 5km race by running 0.75km on the first day, 0.85 the second day and 0.95 third day. If he keeps increasing his distance each day according to the pace of his first three days on what day in his training program will Omar first run at least 5km?
Please show set up of the problem so I understand how to solve... thank you
at an extra 0.1 km/day, on day n he runs 0.65+01n
so, what does n have to be such that
0.65 + 0.1n >= 5.0 ?
So it would actually be 0.75+0.1n>=5.0, since he starts at 0.75
I found this essay on the SSAT practice, and will assume you did as well, and the correct answer choice would be 43 days.
0.75+4.3.=0.5 b/c 0.75+4.3=5.05
15
Well, let's see if we can figure this out with a little bit of humor, shall we?
First, let's set up the problem. We know that Omar starts with 0.75km on the first day, then adds 0.1km each day. So, the distances he runs on the first three days are 0.75km, 0.85km, and 0.95km.
Now, let's imagine Omar's training as a fun little journey. On the first day, he takes a small step, and runs 0.75km. It's like saying, "Hey, I'm just getting started, but watch out world, here I come!"
On the second day, Omar adds another 0.1km. It's like he's saying, "Okay, I'm gaining some momentum here. I can feel the winds of success blowing in my hair!"
And on the third day, he adds another 0.1km. This time, he's really picking up speed. It's like he's saying, "I'm on fire! I'm unstoppable! You better watch out, because I'm coming for that finish line!"
But when will Omar actually run at least 5km? That's the big question. Well, let's calculate it.
On the fourth day, Omar would add another 0.1km, bringing his total distance to 0.95km + 0.1km = 1.05km.
On the fifth day, he would add another 0.1km, bringing his total distance to 1.05km + 0.1km = 1.15km.
This pattern continues with each passing day. Omar keeps adding 0.1km to his total distance.
To figure out when Omar runs at least 5km, we can set up an equation:
0.75 + 0.85 + 0.95 + 0.1n = 5
Now, let's solve it. Let's bring out the math clown!
🤡 *honks nose* Okay, let's solve this equation step by step like a juggling act!
First, let's combine the distances on the left side of the equation:
0.75 + 0.85 + 0.95 = 2.55
So now our equation looks like this:
2.55 + 0.1n = 5
Next, let's isolate the variable n by subtracting 2.55 from both sides:
0.1n = 5 - 2.55
On the right side, if we perform some fancy subtraction, we get:
0.1n = 2.45
Now, let's solve for n by dividing both sides by 0.1:
n = 2.45 / 0.1
So, Omar will run at least 5km on the day when n is equal to:
n = 24.5
But wait, we can't have half a day, can we? So, we round it up to the next whole number.
Therefore, Omar will run at least 5km on the 25th day of his training program!
And there you have it! Omar's humorous journey to running at least 5km! Good luck, Omar, you hilarious running machine! 🏃♂️🤡
To solve this problem, we need to determine the pattern of the increasing distances and find out on which day Omar will run at least 5km.
Omar starts by running 0.75km on the first day, 0.85km on the second day, and 0.95km on the third day. We can see that the distances increase by 0.1km each day.
Therefore, we can set up an equation to represent the distance Omar runs on each day as follows:
Distance on day n = 0.75 + (n - 1) * 0.1
Where n represents the day number.
Now, we can set up an inequality to find out on which day Omar will first run at least 5km:
0.75 + (n - 1) * 0.1 ≥ 5
Simplifying this inequality:
0.75 + 0.1n - 0.1 ≥ 5
0.1n + 0.65 ≥ 5
0.1n ≥ 5 - 0.65
0.1n ≥ 4.35
Now, we can divide both sides of the inequality by 0.1 to isolate n:
n ≥ 4.35 / 0.1
n ≥ 43.5
Since n represents the day number, we round up to the nearest whole number because we can't have fractions of a day. Therefore, Omar will first run at least 5km on the 44th day of his training program.