What is the standard form of the equation of the line that passes through the point (-1, 2) and has a slope of -5?

A. x - 5y = -3
B. x - 20y = -5
C.5x + y = -3
D. 5x - y = 3

I think D

(-1,2), Slope = -5.

Y = mx + b.
2 = -5*(-1) + b,
b = -3.

Y = -5x -3.
5x + y = -3.

d..i take the tests good luck

To find the standard form of the equation of a line, we start with the point-slope form: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

In this case, the slope provided is -5 and the point given is (-1, 2). Substituting these values into the point-slope form, we get:

y - 2 = -5(x - (-1))
y - 2 = -5(x + 1)

Now, we can simplify the equation:

y - 2 = -5x - 5
y = -5x - 3

This equation is in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. To convert it to the standard form (Ax + By = C), we rearrange the equation:

5x + y = -3

So, the standard form of the equation of the line that passes through the point (-1, 2) and has a slope of -5 is 5x + y = -3. Therefore, the correct answer is option C.