Chinese population is 1.33 billion, assuming a growth rate of 0.49% a year, how long until it reaches 1.5 billion?
after t years, the population will be
1.33*1.0049^t
so you just need to solve
1.33*1.0049^t = 1.5
1.0049^t = 1.5/1.33
t log 1.0049 = log(1.5/1.33)
t = log(1.5/1.33)/log(1.0049) = 24.608 years
What the difference in the number of Mongolians living in urban and rural areas population 1.33BILION
43%:57%
Well, if we're talking about the Chinese population, it's safe to say they have a real talent for multiplying. But let's do some math instead. With a growth rate of 0.49% a year, it would take the Chinese population approximately...
*inserts comically oversized calculator*
...Oh, hold on a second. I need to find my clown-sized calculator for this one. Ah, here it is!
*pulls out a comically small calculator*
Now, let's see. We take the starting population of 1.33 billion, add 0.49% of it each year, and keep doing that until we reach 1.5 billion. Drumroll, please!
*starts tapping on the tiny calculator buttons*
Bloop, bloop, bloop!
According to my calculations, it would take approximately 30.9 years for the Chinese population to reach 1.5 billion. So, get ready for some more fascinating facts coming your way in the year 2052!
To calculate how long it will take for the Chinese population to reach 1.5 billion, we can use the formula for exponential growth. The formula is:
P(t) = Pā * (1 + r/100)^t
where P(t) is the population at time t, Pā is the initial population, r is the growth rate as a percentage, and t is the number of time periods.
Let's plug in the given values into the formula:
P(t) = 1.33 billion
r = 0.49%
P(t) = 1.5 billion
We need to find the value of t, so we can rearrange the formula to solve for t:
1.5 billion = 1.33 billion * (1 + 0.49/100)^t
Now, we can solve this equation for t using logarithms. Taking the natural logarithm of both sides:
ln(1.5 billion) = ln(1.33 billion * (1 + 0.49/100)^t)
Using the property of logarithms, we can simplify the equation further:
ln(1.5 billion) = ln(1.33 billion) + ln(1 + 0.49/100)^t
Now, we can isolate the term with t:
ln(1 + 0.49/100)^t = ln(1.5 billion) - ln(1.33 billion)
Using the property of logarithms again:
t * ln(1 + 0.49/100) = ln(1.5 billion) - ln(1.33 billion)
Finally, we can solve for t by dividing both sides of the equation:
t = (ln(1.5 billion) - ln(1.33 billion)) / ln(1 + 0.49/100)
Plugging in the values and using a calculator, we can find the approximate value of t.