What is the value of the greatest of four consecutive integers if the least minus twice the greatest equal 8?

Please show the work so I can understand how to complete the problem - thank you

If x is the greatest, then the numbers are x,x-1,x-2,x-3

You are told that
x-3 - 2x = 8
Now just solve for x

Please help me out

The answer please

To find the value of the greatest of four consecutive integers, let's denote the least integer as "x". Since the numbers are consecutive, the other three integers can be represented as (x+1), (x+2), and (x+3).

According to the given information, the least integer minus twice the greatest equals 8. Mathematically, this can be written as:

x - 2(x+3) = 8

Now, let's solve this equation step by step:

x - 2x - 6 = 8 [distribute -2 to both terms inside the parentheses]
-x - 6 = 8 [combine like terms]
-x = 8 + 6 [add 6 to both sides]
-x = 14
x = -14 [multiply both sides by -1 to solve for x]

Therefore, the least integer is -14. To find the greatest integer, we substitute x = -14 into (x+3):

Greatest Integer = -14 + 3 = -11

Hence, the value of the greatest of four consecutive integers is -11.