The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground?

Given: g = –9.8 meters/second2

h = 0.6g*t^2.

4 = 0.5*9.8t^2.

sup broes

To determine how long it would take an apple falling from a height of 4.00 meters to reach the ground, we can use the formula for calculating the time it takes for an object to fall under gravity.

The formula is:
h = (1/2) * g * t^2,

Where:
h is the height (4.00 meters),
g is the acceleration due to gravity (-9.8 meters/second^2),
and t is the time.

Rearranging the formula, we get:
t^2 = (2h) / g.

Substituting the given values, we have:
t^2 = (2 * 4.00) / -9.8.

Simplifying:
t^2 = -0.8163.

Since time cannot be negative, we will consider the positive square root of -0.8163.

Taking the square root, we find:
t = 0.904 seconds.

Therefore, it would take approximately 0.904 seconds for an apple falling from a height of 4.00 meters to reach the ground.

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