A small cube has a length of 2 inches. How many small cubes are needed to make a larger cube whose base has a perimeter of 32 inches?
side length of big one = 32/4 = 8
volume = 8*8*8
little cube volume = 2*2*2
ratio = 4*4*4= 16*4 = 64
64
64 i tink
Well, if the length of one small cube is 2 inches, then the perimeter of the larger cube would measure 32 inches divided by the length of one small cube, which is 2 inches. So, you would need 16 small cubes to make a larger cube with a base perimeter of 32 inches. Just be careful not to trip over them!
To find out how many small cubes are needed to make a larger cube with a given perimeter, we need to determine the size of the larger cube and then calculate the number of small cubes that can fit inside it.
First, let's calculate the length of the larger cube's side. We know that the base of the larger cube has a perimeter of 32 inches, which means the sum of all its sides is 32 inches. Since the base of the cube is a square, each side length is equal. Thus, we divide the perimeter by 4 (as there are 4 sides in a square) to find the length of one side:
32 inches / 4 = 8 inches
Therefore, the larger cube has a side length of 8 inches.
Now, let's determine how many small cubes can fit inside the larger cube. Since each small cube has a side length of 2 inches, we need to divide the length of the larger cube's side by the length of the small cube's side:
8 inches / 2 inches = 4 small cubes
Hence, we need 4 small cubes to make a larger cube whose base has a perimeter of 32 inches.