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On a hot summer day, a young girl swings on a rope above the local swimming hole. When she lets go of the rope her initial velocity is 2.25 m/s at an angle of 35 degrees above the horizontal. If she is in flight for 0.616 s, how high above the water was she when she let go of the rope?

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3 answers

  1. Your name changes on each post. Are you answer grazing? Appears so. Never trust a person who changes their name on each question.

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  2. = 5.65m.

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  3. There are a whole mess of these questions all basically the same this morning. Read any old answer.
    u = speed * cos angle
    Vi = speed * sin angle
    v = Vi - 9.81 t
    v = 0 at top
    h = Hi + Vi t - 4.9 t^2
    https://www.mathsisfun.com/quadratic-equation-solver.html
    range = u t

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