A ball is projected horizontally from the top of a hill with a velocity of 30m/s.If it reaches the ground 5 seconds later, calculate the height of the hill, take g=10 metres per second square.
My answers is 125 why
H=ut+1\2gt"2 but since its horizntally from the top of a hill,the laws says that u=0,so it will be 1\2gt"2,1\2*10*5"2=5*25,then the answer is 125m
To calculate the height of the hill, we can use the equation of motion for vertical motion:
h = (1/2)gt^2
where h is the height of the hill, g is the acceleration due to gravity (10 m/s^2), and t is the time of flight (5 seconds).
Since the ball is projected horizontally, the initial vertical velocity is 0 m/s. Therefore, the time of flight t is the same as the time taken to reach the ground.
Substituting the values into the equation, we get:
h = (1/2)(10)(5)^2
= (1/2)(10)(25)
= 125 meters
Therefore, the height of the hill is 125 meters.
same answer
U=30m/s
T=5secs
H=?
S=ut+1/2gt^2=0×5×4^2=80metres
a Ball is projected horizontally from the hill with a velocity of 30m if it reaches the ground 5seconds later calculate the height
H=ut +1/2gt×t
30×5+1/2×10×5×5
150+125
=275