How many moles of Nh4+ ions are there in 1.5 moles of (Nh4)3 PO4?
To find the number of moles of NH4+ ions in (NH4)3PO4, we need to consider the ratio between NH4+ ions and (NH4)3PO4.
Looking at the chemical formula (NH4)3PO4, we can see that there are 3 NH4+ ions for every 1 (NH4)3PO4 molecule.
So, for every 1 (NH4)3PO4, there are 3 moles of NH4+ ions.
Given that there are 1.5 moles of (NH4)3PO4, we can calculate the number of moles of NH4+ ions as follows:
Number of moles of NH4+ ions = 1.5 moles (NH4)3PO4 * 3 moles NH4+ ions / 1 mole (NH4)3PO4
Number of moles of NH4+ ions = 4.5 moles NH4+ ions
Therefore, there are 4.5 moles of NH4+ ions in 1.5 moles of (NH4)3PO4.
To find out how many moles of NH4+ ions are there in (NH4)3PO4, we need to analyze the chemical formula of (NH4)3PO4.
The formula indicates that there are 3 NH4+ ions for every 1 molecule of (NH4)3PO4. Therefore, to calculate the number of moles of NH4+ ions, we multiply the total moles of (NH4)3PO4 by the ratio of NH4+ ions to (NH4)3PO4.
In this case, we are given that there are 1.5 moles of (NH4)3PO4. Hence, the calculation is as follows:
Number of moles of NH4+ ions = 1.5 moles (NH4)3PO4 × (3 moles NH4+ ions / 1 mole (NH4)3PO4)
By performing the calculation, we get:
Number of moles of NH4+ ions = 1.5 moles × 3 moles NH4+ ions / 1 mole = 4.5 moles NH4+ ions
Therefore, there are 4.5 moles of NH4+ ions in 1.5 moles of (NH4)3PO4.