A body accelerate uniformly from rest at 2ms-2 .calculate it,s velocity after travelling 9m
u=0
v=?
a=2m/s-2
s=9m
by using v2=u2+2as,we have
v2=zero squared + 2*2m/s-2*9m
v2=0+36
v2=36m/s-2
or square root of 36= 6m/s
well, v = at
now just plug and chug.
and take a look at the definition of PHYSIC
and that's its, not it's, and especially not it,s!!
Give me the correct answer
I need the correct answer please
To calculate the velocity of a body that is accelerating uniformly, you can use the following formula:
v = u + at
Where:
v = final velocity
u = initial velocity (in this case, the body is at rest, so u = 0)
a = acceleration
t = time
In this case, the body is accelerating at a rate of 2 m/s^2 and travels a distance of 9 meters. To find the time it takes, we can use the following formula:
s = ut + (1/2)at^2
Where:
s = distance
u = initial velocity
t = time
a = acceleration
Since the body starts from rest, the initial velocity u = 0. Rearranging the formula:
s = (1/2)at^2
t^2 = (2s)/a
t = sqrt(2s/a)
Substituting the values:
s = 9 meters
a = 2 m/s^2
t = sqrt(2 * 9 / 2) = sqrt(9) = 3 seconds
Now, we can calculate the final velocity using the first formula:
v = u + at
v = 0 + (2 * 3) = 6 m/s
Therefore, the velocity of the body after traveling 9 meters is 6 m/s.
A body a
V=displacement/time
=9×60
=540
V=2/540
=270m.