out of 40 students,14 are taking english and 29 are taking chemistry.if 5 students are in both classes,how many are in neither class?how many students are in either classes?

out of 40 students,14 are taking english and 29 are taking chemistry How many students are taking only English Composition?

total students is 14+29-5 = 38

so, 2 are in no class

There are forty students in a class out of which there are 14 who are taking Maths and 29 who are taking Computer. What is the probability that a randomly chosen student from this group is taking only the Computer class?

Wala

72.5%

Well, well, well, looks like we have quite the academic circus going on here! Let's do some math while juggling digits.

We have 40 students in total - 14 are taking English, and 29 are taking Chemistry. But hold your laughter, because 5 brave souls decided to tackle both subjects at once.

To calculate how many students are in neither class, we need to subtract the number of students in both classes from the total number of students: 40 - 5 = 35. So, 35 students are not taking English nor Chemistry.

Now, let's calculate how many students are in either class. To do that, we sum up the number of students taking English (14), the number of students taking Chemistry (29), and subtract the number of students taking both (5): 14 + 29 - 5 = 38. Voila! 38 students are taking either English or Chemistry (or both if they're up for the challenge).

Now that's what I call a thrilling academic spectacle! Keep those pencils twirling!

To solve this problem, we can use the principle of Inclusion-Exclusion and a Venn diagram to find the number of students in various categories.

Step 1: Draw a Venn diagram with two overlapping circles representing English and Chemistry classes. Label the overlapping region as the number of students taking both classes (5 in this case).

Step 2: Write down the given information:
- The number of students taking English class = 14.
- The number of students taking Chemistry class = 29.

Step 3: Using the Venn diagram, write the number of students belonging to each category:
- The number of students taking only English class = (total English students) - (students taking both classes) = 14 - 5 = 9.
- The number of students taking only Chemistry class = (total Chemistry students) - (students taking both classes) = 29 - 5 = 24.
- The number of students taking either English or Chemistry class = (students taking only English class) + (students taking only Chemistry class) + (students taking both classes) = 9 + 24 + 5 = 38.

Step 4: To find the number of students in neither class, we subtract the number of students taking either English or Chemistry class from the total number of students:
- The number of students in neither class = (total number of students) - (students taking either class) = 40 - 38 = 2.

Therefore, there are 2 students in neither class, and a total of 38 students are taking either English or Chemistry class.