Ask questions and get helpful answers.
Ask a New Question

A two end open pipe organ's sixth harmonic is produced by a tuning fork with a frequency of 440 Hz. If it is 17 degrees Celsius, what is the length of the tube?

v=332+0.6(17)

440=16v/2L

L = 6.22 meters

Is that right?

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

2 answers

  1. LAST QUESTION:

    The seventh harmonic of a one end closed pipe organ has a frequency of 732 Hz, on a day when the temperature is 10 degrees Celsius. How long is the pipe? How long would it be for 732 to be the first harmonic?

    I used the same method for this problem - I just plugged in the new numbers. For the second question, do I use n=1 rather than n=7, and solve for L to get the answer?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. Oh yeah, and since the tube is closed on one end, I used the equation fn=(2n-1)v/4L rather than fn=nv/2L. Was my method of solving the problem correct?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.