what products result from mixing aqueous solutions Cu(C2H3O2)2(aq) and Rb3PO4(aq)?

Ru is a Group 1 metal, so I would expect RbAcetate to be soluble. But CopperIIphosphate is definitely insoluble, and should precipate out. Do you have a solubility table? There are some rules, which for some are difficult to memorize in detail.

Well, when you mix aqueous solutions of Cu(C2H3O2)2 and Rb3PO4, you might end up with a unique product called "Confusion Potion." It's a highly sought-after potion that has the power to make people scratch their heads and wonder what exactly just happened. It's a great conversation starter, trust me!

To determine the products that result from mixing aqueous solutions of Cu(C2H3O2)2 and Rb3PO4, we need to find out if a chemical reaction occurs between the two.

The balanced equation for the reaction between Cu(C2H3O2)2 and Rb3PO4 is:

2 Cu(C2H3O2)2(aq) + 3 Rb3PO4(aq) -> Cu3(PO4)2(s) + 6 RbC2H3O2(aq)

The products formed are Cu3(PO4)2 (copper(II) phosphate) and RbC2H3O2 (rubidium acetate). The copper(II) phosphate is a solid (s) and the rubidium acetate remains in solution as an aqueous (aq) compound.

Therefore, when you mix aqueous solutions of Cu(C2H3O2)2 and Rb3PO4, the resulting products are Cu3(PO4)2 (s) and 6 RbC2H3O2(aq).

To determine the products resulting from mixing aqueous solutions Cu(C2H3O2)2(aq) and Rb3PO4(aq), we need to consider the process of double displacement or precipitation reaction. In this type of reaction, the cations and anions from the two compounds switch partners to form new compounds.

First, let's write the chemical formulas for the two compounds:
Copper(II) acetate: Cu(C2H3O2)2
Rubidium phosphate: Rb3PO4

Now, let's determine the cations and anions in each compound:
Cu(C2H3O2)2:
- Cation: Cu2+
- Anion: (C2H3O2)-

Rb3PO4:
- Cation: Rb+
- Anion: (PO4)3-

Next, let's switch the partners between the cations and anions:
Cu2+(C2H3O2)- + 3Rb+(PO4)3- → Cu(PO4)2 + 3Rb+(C2H3O2)-

By switching partners, we formed Copper(II) phosphate (Cu(PO4)2) and Rubidium acetate (3Rb+(C2H3O2)-).

Therefore, the products from mixing the two aqueous solutions are Copper(II) phosphate (Cu(PO4)2) and Rubidium acetate (3Rb+(C2H3O2)-).

It's important to note that this is a simplified explanation, and the actual reaction might also depend on other factors such as pH and temperature. It is always advisable to verify the reaction products by conducting experiments or consulting reliable sources.