The parametric equations for a line L1 are as follows:
x = −1−2t
y = 4+4t
z = 3−2t
Let L2 be the line parallel to L1 and passing through the point (2, 5, −3). Find the point P on L2 whose xcoordinate is −3.
P = (−3, 0, 0)
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1 answer

The second equation L2 is given by
(x,y,z) = (2,5,3) + t(2,4,2)
we want 3 = 2 2t
2t = 5
t = 5/2
then (x,y,z) = (2,5,3) + (5/2)(2,4,2)
= (2,5,3) + (5, 10, 5) = (3, 15, 8)
the point is (3, 15, 8) 👍
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answered by Reiny
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