Charlie wants us to know the height of a bridge, so he drops a rock over the side. The rock lands in the stream below 3 seconds later. How high is the bridge?
h = 1/2 g t^2 = 1/2 * 9.8 * 3^2
To determine the height of the bridge, we can use the equation for falling objects:
h = (1/2) * g * t^2
Where:
h = height of the bridge
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken for the rock to fall (in seconds)
Given that the rock takes 3 seconds to land, we can substitute these values into the equation:
h = (1/2) * 9.8 m/s^2 * (3 s)^2
Calculating this equation will give us the height of the bridge.
To determine the height of the bridge, we can use the equation of motion for an object in free fall. The equation is:
h = 0.5 * g * t^2
Where:
- h is the height (or in this case, the height of the bridge)
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
- t is the time (in this case, 3 seconds)
To get the height of the bridge, we can plug in the given values into the equation and solve for h:
h = 0.5 * 9.8 * 3^2
h = 0.5 * 9.8 * 9
h = 44.1 meters
Therefore, the height of the bridge is approximately 44.1 meters.