Milk is leaking from a carton at a rate of 3mL/min. There is 1.2 L of milk in the carton at 11:00 a.m.

How much will be left in the carton at 1:00 p.m.?
f(x)=1200-3x

time from 11:00 am to 1:00 pm is 120 minutes

so plug 120 into your equation.
Your answer will be in ml, divide by 1000 if you want it in litres.

Well, let's calculate how much milk will be left in the carton at 1:00 p.m. using the provided information and a touch of mathematical humor.

Since the milk is leaking at a rate of 3 mL/min, we can use the mathematical function:

f(x) = 1200 - 3x,

where x represents the number of minutes that have passed since 11:00 a.m.

Now, let's substitute 120 into the function for x = 60 (since 2 hours have passed, which is the same as 120 minutes):

f(120) = 1200 - 3(120) = 1200 - 360 = 840 mL.

So, there will be 840 mL of milk left in the carton at 1:00 p.m. But don't worry, I won't "milk" this joke any further!

To determine the amount of milk left in the carton at 1:00 p.m., we need to calculate the amount of milk that has leaked out during the 2-hour time period from 11:00 a.m. to 1:00 p.m.

- Convert the starting amount of milk, 1.2 L, to milliliters (mL):
1.2 L * 1000 mL/L = 1200 mL

- Calculate the total amount of milk leaked in 2 hours:
3 mL/min * 120 min = 360 mL

- Subtract the amount leaked from the starting amount to find the remaining milk:
1200 mL - 360 mL = 840 mL

Therefore, there will be 840 mL of milk left in the carton at 1:00 p.m.

To determine the amount of milk that will be left in the carton at 1:00 p.m., we need to calculate the amount of milk that will have leaked out in the 2-hour time period between 11:00 a.m. and 1:00 p.m.

Given that the milk is leaking at a rate of 3 mL/min, we can use this information to determine the amount of milk lost per minute.

Let's set up an equation to represent the amount of milk left in the carton at any given time, measured in minutes since 11:00 a.m.:

f(x) = 1200 - 3x

In this equation, f(x) represents the amount of milk in milliliters that is left in the carton after x minutes.

To find the amount of milk left at 1:00 p.m. (which is 120 minutes after 11:00 a.m.), we substitute x = 120 into the function:

f(120) = 1200 - 3 * 120
f(120) = 1200 - 360
f(120) = 840 mL

Therefore, there will be 840 mL (or 0.84 L) of milk left in the carton at 1:00 p.m.