a test tube containing CaCo3 is heated until all the compound decomposes. If the test tube plus calcium carbonate originally weighed 30.08 grams and the loss of mass during the experiment is 4.40 grams, what was the mass of the empty test tube?

Write the equation.
CaCO3 ==> CaO + CO2

First, the equation isn't quite clear. The questions gives the impression that CaCO3 COMPLETELY decomposes; in reality, it decomposes into CO2 (which is the loss in mass) but it leaves CaO.
Convert 4.40 g CO2 to mols CO2. Convert that to mols CaCO3. Convert that to grams CaCO3.
Then grams CaCO3 + test tube = 30.08 g
less grams CaCO3 = ??
The difference is the mass of the test tube.

To find the mass of the empty test tube, we need to determine the mass of the CaCO3 that decomposed.

1. Convert 4.40 grams CO2 to moles. To do this, we need to know the molar mass of CO2, which is 44.01 grams/mol.

Moles of CO2 = (mass of CO2) / (molar mass of CO2)
= 4.40 g / 44.01 g/mol
= 0.100 mol CO2

2. Determine the moles of CaCO3. According to the balanced equation, 1 mole of CaCO3 decomposes to 1 mole of CO2.

Moles of CaCO3 = Moles of CO2
= 0.100 mol CO2

3. Convert the moles of CaCO3 to grams. The molar mass of CaCO3 is 100.09 g/mol.

Mass of CaCO3 = (moles of CaCO3) * (molar mass of CaCO3)
= 0.100 mol * 100.09 g/mol
= 10.009 g CaCO3

4. Now, we can calculate the mass of the empty test tube.

Mass of empty test tube = (mass of CaCO3 + test tube) - mass of CaCO3
= 30.08 g - 10.009 g
= 20.071 g

Therefore, the mass of the empty test tube is approximately 20.071 grams.

To find the mass of the empty test tube, we need to follow a series of steps:

Step 1: Calculate the number of moles of CO2 produced.
Since 4.40 grams of CO2 were released during the decomposition, we need to convert this mass to moles. First, we need to determine the molar mass of CO2. The molar mass of carbon (C) is approximately 12.01 grams/mol, and the molar mass of oxygen (O) is approximately 16.00 grams/mol. Since CO2 contains one carbon atom and two oxygen atoms, its molar mass is 12.01 + (16.00 x 2) = 44.01 grams/mol.

To calculate the number of moles of CO2, divide the mass of CO2 by its molar mass:
moles of CO2 = 4.40 g / 44.01 g/mol = 0.10 mol CO2

Step 2: Find the number of moles of CaCO3.
For every one mole of CO2 produced during the decomposition, one mole of CaCO3 is consumed. Therefore, the number of moles of CaCO3 in the reaction is equal to the number of moles of CO2 produced. In this case, it is 0.10 mol.

Step 3: Calculate the mass of CaCO3.
To find the mass of CaCO3, multiply the number of moles of CaCO3 by its molar mass. The molar mass of CaCO3 is calculated by adding the molar masses of calcium (Ca), carbon (C), and three oxygen atoms (O). The molar mass of calcium is approximately 40.08 g/mol, carbon is 12.01 g/mol, and oxygen is 16.00 g/mol.
molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (16.00 g/mol x 3) = 100.09 g/mol

mass of CaCO3 = 0.10 mol x 100.09 g/mol = 10.01 g

Step 4: Calculate the mass of the empty test tube.
The total mass of the test tube plus the CaCO3 initially was given as 30.08 grams. From this, we subtract the mass of the CaCO3 obtained in the previous step to find the mass of the empty test tube.
mass of empty test tube = 30.08 g - 10.01 g = 20.07 g

Therefore, the mass of the empty test tube is 20.07 grams.

the mass of the test tube is 20.1 grams

24.50