A patient receives 3.2 L of glucose solution intravenously (IV). If 100. mL of the solution contains 5.0 g of glucose (carbohydrate), how many kilocalories did the patient obtain from the glucose solution?

*If anyone could help me with this, please show your work so I can understand how you came to your answer =)

Well, I may not be the most scientific bot out there, but I'll give it a shot! Let's break it down step by step.

First, we need to figure out how many grams of glucose the patient received. We know that 100 mL of the solution contains 5.0 g of glucose, so we can set up a proportion:

100 mL is to 5.0 g as 3200 mL (3.2 L) is to X g

Using cross-multiplication, we can find X:

(100 mL)(X g) = (5.0 g)(3200 mL)
100X = 16000
X = 160 g

So the patient received 160 grams of glucose.

Now, we need to determine the number of kilocalories provided by this amount of glucose. Each gram of glucose provides 4 kilocalories, so:

160 g × 4 kcal/g = 640 kcal

So the patient obtained 640 kilocalories from the glucose solution. I hope that helps!

To find the number of kilocalories obtained from the glucose solution, we'll need to follow these steps:

Step 1: Calculate the total amount of glucose (in grams) received by the patient.

To do this, we'll use the given information that 100 mL of the solution contains 5.0 g of glucose. First, we need to determine how many 100 mL units are there in 3.2 L:

3.2 L = 3.2 x 1000 mL = 3200 mL

So, there are 3200 mL in 3.2 L.

Now, let's calculate the amount of glucose received by the patient:

3200 mL / 100 mL = 32

Since there are 32 units of 100 mL in the total volume, the patient received 32 times the amount of glucose in each 100 mL unit:

32 units x 5.0 g = 160 g

Therefore, the patient received 160 g of glucose.

Step 2: Convert the amount of glucose (in grams) to kilocalories.

To convert grams of glucose to kilocalories, we'll need to use the conversion factor that 1 gram of glucose provides 4 kilocalories.

Let's calculate the number of kilocalories obtained from the glucose solution:

160 g x 4 kcal/g = 640 kcal

Therefore, the patient obtained 640 kilocalories from the glucose solution.

So, the answer is 640 kilocalories.

1L = 1000 ml

3.2L = (1000x3.2)ml = 3200 ml
100 ml solution contain 5.0 g of glucose
3200 ml solution contai( 5.0g x 3200ml)/100 ml
= 160 g
Therefore,
Mass is 160g
We know that the energy value of carbohydrate in kcal is 4
So, 160g x 4kCal/g
= 640 kCal

802.4

How much glucose is in the 3.2 L? That's

5.0 g glucose x (3,200 mL/100 mL) = ? g glucose.
Then each g glucose has 4 kcal.
You finish.