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A rectangular piece of metal is 15in longer than it is wide. Squares with sides 3 in long are cut from four corners and the flaps are folded up to form an open box. If the volume is 1218in^3, what we’re the original deminsions of the piece of metal?

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3 answers

  1. Interesting. Are you able to visualize this? Any idea how to get started?

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    Leo
  2. X^2+3x-1272=0
    Needs to be factored

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  3. original piece is x by x+15

    base of box = x-6 by x+9
    height of box = 3

    volume = 3(x-6)(x+9) = 1218
    x^2 + 3x - 54 = 406
    x^2 + 3x - 460 = 0
    (x - 20)(x + 23) = 0
    x = 20 or a negative

    the original piece was 20 by 35 inches

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