In a solution of Al2(SO4)3 the Al3+ concentration is .12 M. What mass of Al2(SO4)3 is in 50 mL of this solution. Please explain the steps. Thanks. The Al3+ part confuses me the most.
If Al^3+ is 0.12M, that means you must have 0.06M Al2(SO4)3. If you want to do it mathematically, then
0.12 M Al^3+ x (1 mole Al2(SO4)3/2 moles Al^3+) = 0.06 M.
Then we know 0.06M means 0.06 moles/L or 0.06 moles/1000 mL. The amount in 50 mL must be
0.06 moles x (50/1000) =?? moles.
But since Al3+ is only one Al doesn't it equal the moles of the compound, and Al2 would be .24 M? Basically why is Al3+ considered Al2? Isnt Al3 just the ionic version of Al?
In a solution of Al2(SO4)3, the Al3+ concentration is 0.12 M. What mass of Al2(SO4)3 is in 50 mL of this solution?
Who can solve please..please help me
In a solution of Al2(SO4)3, the Al3+ concentration is 0.12 M. What mass of Al2(SO4)3 is in 50 mL of this solution?
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To determine the mass of Al2(SO4)3 in the solution, you need to use the given concentration and the volume of the solution. Here are the steps to calculate it:
Step 1: Understand the given information.
- The concentration of Al3+ ions is 0.12 M, which means there are 0.12 moles of Al3+ ions in 1 liter (1000 mL) of solution.
- The volume of the solution is 50 mL.
Step 2: Convert the volume of the solution to liters.
Since the concentration is given in moles per liter, we need to convert the volume to liters to obtain consistent units.
- 50 mL/1000 mL/L = 0.05 L
Step 3: Calculate the moles of Al3+ ions in the solution.
Using the concentration and the volume converted to liters, you can calculate the moles of Al3+ ions present in the solution using the formula:
moles = concentration × volume
- Moles of Al3+ = 0.12 M × 0.05 L = 0.006 moles
Step 4: Determine the molar ratio of Al2(SO4)3 to Al3+ ions.
From the chemical formula Al2(SO4)3, we can see that it contains two moles of Al3+ ions for every one mole of Al2(SO4)3. This molar ratio is important to convert moles of Al3+ ions to moles of Al2(SO4)3.
Step 5: Calculate the moles of Al2(SO4)3.
Since the molar ratio is 2:1 (Al2(SO4)3:Al3+), you can calculate the moles of Al2(SO4)3 using the formula:
moles of Al2(SO4)3 = moles of Al3+ / molar ratio
- Moles of Al2(SO4)3 = 0.006 moles / 2 = 0.003 moles
Step 6: Determine the molar mass of Al2(SO4)3.
The molar mass of Al2(SO4)3 can be calculated by summing the atomic masses of each element: Al (26.98 g/mol), S (32.07 g/mol), and O (16.00 g/mol). Therefore:
Molar mass of Al2(SO4)3 = 2(26.98 g/mol) + 3(32.07 g/mol) + 12(16.00 g/mol) ≈ 342.15 g/mol
Step 7: Calculate the mass of Al2(SO4)3.
Using the molar mass of Al2(SO4)3 and the calculated moles, you can find the mass of Al2(SO4)3 using the formula:
mass = moles × molar mass
- Mass of Al2(SO4)3 = 0.003 moles × 342.15 g/mol ≈ 1.03 g
Therefore, the mass of Al2(SO4)3 in 50 mL of the solution is approximately 1.03 grams.