Ask questions and get helpful answers.

Solve: dA/dt = -10A, A(0) = 5

------------------

I tried getting A by itself:

A = -1/10 * dA/dt
A(0) = 5 = -1/10 * dA/dt

but I'm somewhat sure that's wrong; so integrating I get:

int(dA/dt) = int(-10A)
A = -5A^2

which doesn't make sense to me intuitively since the same variable is on both sides. I'm a bit confused, any help is appreciated.

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
2 answers
  1. A = -1/10 * dA/dt
    dA/A=-10dt
    lnA=-10t+C
    when t=0, A=5
    ln5=C
    LnA=-10t+ln5

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    👤
    bobpursley
  2. ah, I see! thank you

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.