A cube made ouk and side 15cm floats in water with 10.5cm of it's depth below the surfaces and with it's side's vertical what is density of oak
That's actually wrongðŸ˜
It is really tough and wrong
To find the density of oak, we need to know the mass of the cube. However, the given information only provides the dimensions of the cube and its submerged depth.
To solve this problem, we can use the concept of buoyancy. When an object floats in a fluid, the buoyant force acting on the object is equal to the weight of the fluid displaced by the object.
From the given information, we can determine the volume of the submerged part of the cube. The submerged volume is the product of the cross-sectional area of the cube's face and the submerged depth. So, the submerged volume is:
Submerged volume = face area * submerged depth
Since the cube is a regular cube, all of its faces have the same area. The area of one face is simply the side length squared. Therefore, the submerged volume is:
Submerged volume = (side length^2) * submerged depth
Substituting the given values:
Submerged volume = (15 cm^2) * 10.5 cm
After calculating the submerged volume, we can determine the volume of the entire cube using the same formula. Since the entire cube is floating, the entire volume equals the submerged volume. So:
Total volume = Submerged volume = (15 cm^2) * 10.5 cm
Finally, we can calculate the density using the formula:
Density = Mass / Volume
However, to find the mass, we need additional information, such as the density of oak or the total weight of the cube. Without this information, we cannot determine the density of oak.
volume of oak under water = 15*15 * 10.5
so Archimedes says
mass of oak = density of water * volume under water = 1 g/cm^3 * 15*15 * 10.5
total volume of oak = 15*15*15
density = mass/volume = 1 g/cm^3 * 10.5/15