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What is the pH of a 0.25 M acetic acid solution if the Ka of acetic acid is 1.8 x 10-5?


2.67
0.60
5.34
11.33

I got A, 2.67. I think this is correct as well since acetic acid is a weaker acid and the ph # would make sense.

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2 answers

  1. CH3CO2H → CH3CO2− + H+

    [CH3CO2−] [H+] / [CH3CO2H] = 1.8E-5

    x^2 / (.25 - x) = 1.8E-5 ... x^2 + 1.8E-5 x - 4.5E-6 = 0 ... x = 2.11E-3

    log(2.11E-3) = 2.67 ... good choice

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  2. Scott you a Dawg brother

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