# Okay so I have looked a lot of places for some help on my math test. I am going to put down the first 3 questions and answer choices on my test. If you have the same test as I do then could you give me some answers ASAP? Remember, all test aren't the same and I'm a Connection Academy Student for the 7th grade. I at probability and if I fail... well.... the results will be devastating to my grade and to me. HELP!!!!!!!!!!!!

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Question 1
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Jerry mixes the letters F,P,M,M,M,F,P and J thorough. Without looking Amanda draws one letter. Expressed as a fraction, decimal and percentage. What is the probability that J will NOT be the letter Amanda selects?

A.7/8, 0.875, 87.5%

B.5/8, 0.625, 62.5%

C.1/8 , 0.125, 12.5%

D.8/7, 1.14, 11.4%
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Question 2
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Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Allen draws one letter. Expressed as a fraction, decimal, and percentage, what is the probability that Allen will not select a consonant?

A. 3/8 , 0.375, 37.5%
B. 3/5 , 0.6, 60%
C. 5/8 , 0.625, 62.5%
D. 1/2 , 0.5, 50%
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Question 3
_______________________________________________________________________Suppose you have a drawer full of white, black and yellow pairs of socks. If the probability of picking a white pair of socks is 4/9, and the probability of picking a black pair of socks is 7/18, what is the probability of picking a yellow pair of socks?

A. 1/6
B. 5/12
C. 7/15
D.16/27

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1. You should probably start from the basics here: https://www.khanacademy.org/math/statistics-probability

If you've reached the test for the course and you have no idea about these questions, you need to start over. (Sad to say, but I'd be in your shoes. I would have to start over!)

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2. 1. Since J is one of the 8 letters , it is 1/8 of the total letters. Therefore, there's a 7/8 probability that you'll not draw a J.

2. How many of these 8 letters are not vowels?

3. 8/18 + 7/18 = 15/18 are not yellow

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3. My goodness, I would expect my students to be able to answer these after the introductory lesson to probability .

The only one that could pose a problem is the third.

There are 3 events, the sum of the probabilities must be 1
prob(white) + prob(black) + prob(yellow) = 1
4/9 + 7/18 + x = 1

solve for x

for the 1st , find the prob(picking a J),
then prob(NOT picking a J) = 1 - answer = ...

2nd, the same thing.

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4. Thanks Ms. Sue!!! YOU. ARE. A. LIFESAVER!!!!!!!!!!!!!!!!!!!

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