Find concentration acid in 50ml of 1.0 M NaOH is titrated with 75ml of sulfuric acid
2. 120cubic centimeter of 0.8m NaOH is titrated with 150cubic centimetre of nitric acid
1. 50*1*1=75*2*C solve for concentration C. I assume you understand the titrationequationi.
2. 120*.8*1=150*C*1 solve for C
To find the concentration of acid in a titration, we need to use the concept of balanced chemical equations and stoichiometry.
1. For the first question:
Given:
- Volume of NaOH solution (base) = 50 mL
- Concentration of NaOH solution = 1.0 M
- Volume of sulfuric acid solution (acid) = 75 mL
- We're assuming a 1:1 stoichiometry for the reaction between NaOH and sulfuric acid.
To determine the concentration of the acid (sulfuric acid), we can use the following equation:
NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + H2O(l)
By comparing the number of moles of NaOH with the number of moles of sulfuric acid used in the reaction, we can determine the concentration of the acid.
Step-by-step solution:
1. Calculate the number of moles of NaOH:
Moles of NaOH = Concentration of NaOH × Volume of NaOH solution
Moles of NaOH = 1.0 M × 0.05 L (50 mL converted to L)
2. From the balanced equation, we can see that 1 mole of NaOH reacts with 1 mole of H2SO4.
Therefore, the number of moles of H2SO4 = Moles of NaOH (from step 1)
3. Calculate the concentration of H2SO4:
Concentration of H2SO4 = Moles of H2SO4 / Volume of H2SO4 solution
Concentration of H2SO4 = Moles of H2SO4 / 0.075 L (75 mL converted to L)
Now, plug in the values and calculate the concentration of H2SO4.
2. For the second question:
Given:
- Volume of NaOH solution (base) = 120 mL
- Concentration of NaOH solution = 0.8 M
- Volume of nitric acid solution (acid) = 150 mL
- We're assuming a 1:1 stoichiometry for the reaction between NaOH and nitric acid.
To determine the concentration of the acid (nitric acid), we can use the balanced equation and stoichiometry:
NaOH(aq) + HNO3(aq) → NaNO3(aq) + H2O(l)
Follow the same steps as explained in the first question to calculate the concentration of nitric acid.
Please let me know if you would like me to provide the detailed step-by-step calculations for either of the questions.
To find the concentration of acid in a titration, you need to use the concept of stoichiometry. The balanced chemical equation for the reaction will help us determine the ratio of acid to base, which is essential for calculating the concentration.
In the first question, 50 mL of 1.0 M NaOH is titrated with 75 mL of sulfuric acid. The balanced equation for this reaction is:
2 NaOH + H2SO4 → Na2SO4 + 2 H2O
From the equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4. Therefore, to calculate the concentration of the sulfuric acid, we need to find out how many moles of NaOH were used in the reaction.
Step 1: Calculate the number of moles of NaOH used:
Moles of NaOH = volume of NaOH (in liters) x concentration of NaOH (in mol/L)
Moles of NaOH = (50 mL / 1000 mL/L) x (1.0 mol/L)
Moles of NaOH = 0.05 mol
Step 2: Determine the number of moles of H2SO4 based on the stoichiometry of the reaction.
From the balanced equation, we know that 2 moles of NaOH react with 1 mole of H2SO4.
Therefore, moles of H2SO4 = (0.05 mol of NaOH) / (2 mol of NaOH/1 mol of H2SO4) = 0.025 mol of H2SO4.
Step 3: Calculate the concentration of sulfuric acid:
Concentration of H2SO4 = moles of H2SO4 / volume of H2SO4 (in liters)
Concentration of H2SO4 = 0.025 mol / (75 mL / 1000 mL/L)
Concentration of H2SO4 = 0.333 M
Therefore, the concentration of sulfuric acid in the given titration is approximately 0.333 M.
Similarly, you can follow the same steps for the second question.
In the second question, 120 mL of 0.8 M NaOH is titrated with 150 mL of nitric acid (HNO3). The balanced equation is:
HNO3 + NaOH → NaNO3 + H2O
From the equation, we can see that 1 mole of NaOH reacts with 1 mole of HNO3. Therefore, to determine the concentration of nitric acid, we need to find how many moles of NaOH were used in the reaction.
Step 1: Calculate the number of moles of NaOH used:
Moles of NaOH = volume of NaOH (in liters) x concentration of NaOH (in mol/L)
Moles of NaOH = (120 mL / 1000 mL/L) x (0.8 mol/L)
Moles of NaOH = 0.096 mol
Step 2: The stoichiometry of the reaction shows that 1 mole of NaOH reacts with 1 mole of HNO3. Therefore, the moles of HNO3 in the reaction are also 0.096 mol.
Step 3: Calculate the concentration of nitric acid:
Concentration of HNO3 = moles of HNO3 / volume of HNO3 (in liters)
Concentration of HNO3 = 0.096 mol / (150 mL / 1000 mL/L)
Concentration of HNO3 = 0.64 M
Thus, the concentration of nitric acid in the given titration is approximately 0.64 M.