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My question is “The line passes through the points (-4.5, 2) and (6.3, 5.8).” I have to create an equation in y=mx+b form for these points. Can someone please help me. I don’t know how to solve this, because I wasn’t taught it. Please just give any help you can. Thank You!

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3 answers

  1. y=mx+b You have one equation, two unknowns, and you have two solutions given, so, you can solve it. Start with the first point (-4.5, 2)
    Y=mx+b
    2=m(-4.5)+b
    2=-4.5m+b Now the second point (6.3, 5.8)
    5.8=6.3m+b Now you have two equations, two unknowns
    2=m(-4.5)+b
    5.8=6.3m+b
    subtract the first equation from the second...
    3.8=10.8m so you have m.
    then put m into either equation, and solve for b

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  2. Thanks

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  3. or

    slope = (5.8 - 2)/(6.3+4) = 3.8/10.8 = 19/54

    so the equation is y = (19/54)x + b
    sub in the "easiest point", namely (-4.5 , 2)
    2 = (19/54)(-9/2) + b , -4.5 = -9/2
    2 + 19/12 = b
    b = 43/12

    y = (19/54)x + 43/12

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