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A box contains 12 bulbs with 3 defective ones. If two bulbs are drawn from the box together.what is the probability that a)both bulbs are defetive b)both are non defective c)one bulb is defective?

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3 answers

  1. 3/20

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  2. what will be the answer

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  3. If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

    c) 3/12 * 9/(12-1) = ?

    Use the similar process for a and b.

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