All i need is an equation of the hyperbola.
given that the center is at (2, 3), the vertices are at (2, 3) and (2,  9), and the foci are at (2, 3 ± 2√10).
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1 answer

The transverse axis is vertical. You have
a=6
c=2√10
so, b^2 = c^2a^2 = 4036 = 4, so b=2
Thus , the equation is
(y+3)^2/36  (x2)^2/4 = 1 👍
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Steve
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