Ask questions and get helpful answers.

Water of mass 120g at 50°c is added to 200g of water at 1 0°c and the mixture is well stirred . calculate the temperature of the mixture .(neglect heat losses to the surrounding)

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

5 answers

  1. sum of heats gained is zero.
    heatgainedhotwater+heatgainedbycoolwater=0
    120*c*(Tf-50)+200*c*(Tf-10)=0
    solve for Tf

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. Thank u

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. pls wats the answer

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. to learn

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  5. water of mass 120g

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.