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A grocer wants to mix nuts costing $5 per kg with nuts costing $8 per kg to make a 10 kg mixture selling for $6 per kg. How much of each type should be mixed?

How do I set up this problem? Thank you.

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1 answer

  1. let E be weight of expensive nuts, C be cheaper nuts
    E*8+C*5=10*6 value equation
    E+C=10 mass equation

    Solve it by any method, I will do determinants

    Det: 8-5=3
    E= (60-50)/3=10/3 =3.33 lb
    C= 80-60 /3=20/3 =6.66 lb

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    bobpursley

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