A car is speeding along the motorway at 40 m s when the driver
observes an accident ahead. He slams on the brakes, the wheels lock immediately, and the car skids to a halt. You may assume that the car travels in a straight line whilst it is skidding and that the magnitude of its deceleration is 10 m s^2.
What distance does the car travel between the time that the brakes are applied and the time that the car comes to rest, and how much time does this take?
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2 answers

time to stop = t
v = Vi  10 t
0 = 40  10 t
t = 4 seconds to stop
d = average speed during stop * time = 20 * 4 = 80 meters 👍
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Damon 
a. V^2 = Vo^2 + 2a*d = 0,
40^2 + (20)d = 0,
d = 80 m.
b. V = Vo + a*t = 0,
40 + (10t = 0,
t = 4 s. 👍
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Henry
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