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If you have 10.00 mL of 0.5875 M H3PO4, how many mL of 0.2625 M NaOH are needed to reach the point of complete neutralization?

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  1. Na*Va=Nb*Vb
    .5875*3*10ml=.2625*Vb

    Vb= 10ml*(.5875/.2625)= about 22ml in my head

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