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Sulfuric acid is diluted in water to make new mixtures. In one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31$ acid solution. The contents of the containers are mixed together? What's the percentage strength of the acid in the mixture?

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2 answers

  1. 14 % = 0.14

    31 % = 0,31

    Total volume of containers:

    72 ml + 64 ml = 136 ml

    Volume of acid in first container:

    72 ml * 0.14 = 10.08 ml

    Volume of acid in second container:

    64 ml * 0.31 = 19.84 ml

    Volume of alcohol in the mixture :

    10.08 ml + 19.84 ml = 29.92 ml

    Percentage strength of the acid in the mixture:

    ( 29.92 / 136 ) * 100 % = 0.22 *100 % = 22 %

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  2. .14 * 72 = ? mL acid

    .31 * 64 = ? mL acid

    64 + 72 = ? mL mixture

    divide the TOTAL mL of acid by the mixture volume to find the % acid

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