Find the real root of the equation 3xcosx1=0 correct to four decimal places using the Newton Raphson Method.
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2 answers

Find a real root of the equation x3 – x – 1 = 0 using Newton  Raphson method, correct to four decimal places.
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answered by alizain123 
let y = 3x  cosx  1
y' = 3 + sinx
newx = oldx  (3oldx  cos(oldx)  1)/(3 + sin(oldx))
let's take a look
http://www.wolframalpha.com/input/?i=plot+y+%3D+3xcosx1
it appears x = .5 could be a good start
x ..... newx
.5  .6085..
.6085 .60710
.60710 .60710 < same result correct to 5 decimals
check in original:
LS = 3(.60710)  cos(60710)  1
= .0000058... , not bad 👍
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answered by Reiny
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