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For what value of x are 16i-12j+4k and xi-(x-1)j+k parallel?

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  1. To be parallel:
    x/16 = -(x-1)/-12= 1/4

    using x/16 = 1/4
    4x = 16
    x = 4

    does that work for -(x-1)/-12 ??
    sub in x = 4 to get
    -(4-1)/-12
    = 3/12 = 1/4, YES

    x = 4

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