For what value of x are 16i12j+4k and xi(x1)j+k parallel?
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1 answer

To be parallel:
x/16 = (x1)/12= 1/4
using x/16 = 1/4
4x = 16
x = 4
does that work for (x1)/12 ??
sub in x = 4 to get
(41)/12
= 3/12 = 1/4, YES
x = 4 👍
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answered by Reiny
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