A little confused on this question... I think I would need to take the solute and put it over the solvent, and then use molar mass. Confused on how density plays into this problem.

Sucrose is very soluble in water. At 25ºC, 211.4 grams of sucrose will dissolve in 100 g of water. Given that the density of the saturated sucrose solution is 1.34 g/mL, what is the molarity of the solution? The molar mass of sucrose is 342 g/mol.

To find the molarity of the solution, we need to use the given information about the mass of solute and the volume of the solution.

First, we need to determine the volume of the solution. We are given the mass of the solvent (water) and its density. Using the formula:

volume = mass / density

We can calculate the volume of water by dividing the given mass of 100 g by the density of 1.34 g/mL.
volume = 100 g / 1.34 g/mL = 74.63 mL

Next, we need to convert the volume of water to liters, as molarity is expressed in moles per liter (mol/L).
volume = 74.63 mL / 1000 mL/L = 0.07463 L

Now, we can calculate the number of moles of sucrose (solute) that dissolved in the given amount of water.
moles of sucrose = mass of sucrose / molar mass of sucrose

The mass of sucrose is given as 211.4 g, and the molar mass of sucrose is 342 g/mol.
moles of sucrose = 211.4 g / 342 g/mol = 0.618 mol

Finally, we can use the number of moles of sucrose and the volume of the solution to calculate the molarity using the formula:

molarity = moles of solute / volume of solution

Substituting the values, we have:
molarity = 0.618 mol / 0.07463 L = 8.29 mol/L

Therefore, the molarity of the sucrose solution is 8.29 mol/L.

M = mols/L solution. The density is given so that you can convert the 100 g of solution into a volume.

mols = grams sucrose/molar mass sucrose = ?
mass solution = (100+211.4) = volume in mL x density in g/ml. Substitute and solve for volume in mL and convert to L, then find M.