If f is a vectorvalued function defined by <sin2t, cos2t> then what is f '' (pi/4)?
I think it is <4, √2/2>.
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2 answers

Sorry...it is cost, not cos2t.
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answered by Anonymous 
x= sin 2 t
y = cos t
x' = 2 cos 2t
y' = sin t
x" =  4 sin 2t
y" = cos t
at pi/4
sin pi/2 = 1
cos pi/4 = sqrt 2/2
so yes , (4 , sqrt 2 / 2 ) 👍
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answered by Damon
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