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Nitrogen reacts with powdered aluminum according to the reaction:

2Al(s)+N2(g)→2AlN(s)

How many liters of N2 gas, measured at 892 torr and 98 ∘C, are required to completely react with 17.8 g of Al?

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5 answers

  1. mols Al = grams/atomic mass = ?
    Using the coefficients in the balanced equation, convert mols Al to mols N2. That is mols Al x (1 mol N2/2 mols Al) = ?
    Now use PV = nRT with the conditions listed to solve for V. Post your work if you get stuck.

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  2. is this the right setup? (1.174) x V= (36)(0.0821)(371)

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  3. correction: (1.174) x V= (8.9)(0.0821)(371)

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  4. The set up is OK but n doesn't look right to me.

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  5. How do you calculate n specifically?

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